1x9 2


πconst▼ const. xvar▼ var. 1/x% %.

(4 балла)Решите систему неравенств:{x+ 2 < 17 - 2x{9 - 5x < 24.

(x+9)(x−9). x^2-7x+12.

Дано уравнение: x 2 3 x 3 x 2 1 x Найти: x

1X. 12. 2X. Б. Тотал.

2.Решите уравнения: 1) |x|=9,6 2)|x|= -4.

Split the limit using the Sum of Limits Rule on the limit as x. x. approaches ∞. ∞. . √limx→∞9+limx→∞1x2limx→∞4−3x. limx→∞⁡9+limx→∞⁡1x2limx→∞⁡4-3x. Since its numerator approaches a real number while its denominator is unbounded, the fraction 1x2.

Expand left side and rewrite with right side equal to zero. x2 - 6x + 9 = 0 Factor left side. (x - 3)2 = 0 Solve for x. x - 3 = 0 solution set: {3}. The equation √x= - 1 has no real solution because the square of a real number is greater than or equal to zero. Square both sides. (√x)2 = 52 Simplify. x = 25.

Источник задания: Задание 5. Найдите корень уравнения 16^(x-9) = 1/2.

Условие. Решите уравнение: 1) (x + 9)^2 − x(x + 8) = 1; 2) (x − 11)^2 = (x − 7)(x − 9); 3) (x − 4)(x + 4) − (x + 6)^2 = − 16; 4) (1 − 3x)^2 − x(9x − 2) = 5.

Тогда решением будут \(t\in (-\infty;3]\cup(5;9)\). Вернемся к прежней переменной: \[\left[\begin{gathered}\begin{aligned} &3^x\leqslant 3\\[1ex] &5<3^x<9 \end{aligned}\end{gathered}\right.\quad\Leftrightarrow\quad \left[\begin{gathered}\begin{aligned}...

Given, x+1/x = 9 , Squaring both sides. x+1/x=9 equation(1). On the square of both sides.

Решите уравнение: а) (x − 1)(x − 7) = 0; б) (x + 2)(x − 9) = 0; в) (x − 11)(x + 6) = 0; г) (x + 1)(x − 1)(x − 5) = 0; д) x(x + 3)(x + 3) = 0; е) (x − 4)(x + 9)(x + 13) = 0. (x − 1)(x − 7) = 0 x − 1 = 0.

а) Решите уравнение 8^x-9*2^(x+1)+2^(5-x)=0.

Первое 9; второе 1; третья 4,8;1) x=9; -92) нет решения3) х=4,8.

OcenaOcena9 sty 2019 Ocena 149,00zł W magazynie12 gru 2015 Ocena29 mar 2019 Ocena29 mar 2019 Ocena7,00złW magazynie3399,00złBrak w magazynie1,17zł

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